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## find the common difference of -34 -29 -24 – 19

**Pertanyaan: **find the common difference of -34 -29 -24 – 19

-10

maybe that the answer

## find the sum of the terms of an infinite geometric

**Pertanyaan: **find the sum of the terms of an infinite geometric sequence whose first term is 4 and common ratio ⅕

” Barisan Geometri “

**_****_****_****_****_****_****_****_****_****_**

>>>__D____i____k____e____t____a____h____u____i____ ____:__

a = 4

r = ⅕

**_****_****_****_****_****_****_****_**

>>> S∞ = ….

**_****_****_****_****_****_****_****_****_****_****_**

**[tex] sf S_{ infty } = frac{a}{1 – r} [/tex]**

**[tex] sf S_{ infty } = frac{4}{1 – frac{1}{5} } [/tex]**

**[tex] sf S_{∞} = frac{4}{ frac{4}{5} } [/tex]**

**[tex] sfto 4 div frac{ 4}{5} \ sf to cancel{4} times frac{5}{ cancel{4}} [/tex]**

[tex] boxed{ sf S_{∞} = 5}[/tex]

**_****_****_****_****_****_****_****_****_****_****_****_**

**C****M****I****I****W**

Ciyo.

## Find the sum of the positive terms of the arithmetic

**Pertanyaan: **Find the sum of the positive terms of the arithmetic sequence 85, 78, 71,

**Jawaban:**

78,85,71

**Penjelasan dengan langkah-langkah:**

maaf kalo salah

## the first term of an arithmetic progression is 3, the

**Pertanyaan: **the first term of an arithmetic progression is 3, the fourth term is 15 and the 16th term is 63, find the common difference of this progression.

**Jawab:**

b = difference = 4

**Penjelasan dengan langkah-langkah:**

U1 = 3, U4 = 15, U16 = 63

U1 = a = 3

U4 = a + 3b

15 = 3 + 3b

3b = 15 – 3 = 12

b = 12/3 = 4

## given the sequence as 1,1,2,3,5,8,13,… . The tenth term of

**Pertanyaan: **given the sequence as 1,1,2,3,5,8,13,… . The tenth term of that arithmetic sequence is … .

1 , 1 , 2 , 3 , 5 , 8 , 13 , 21 , 34 , 55

1 + 1 = 2

2 + 1 = 3

3 + 2 = 5

5 + 3 = 8

8 + 5 = 13

13 + 8 = 21

21 + 13 = 34

34 + 21 = 55

The tenth term of that arithmetic sequence is 55

**Jawab:**

The tenth term of that arithmetic sequence is **89**

**Penjelasan dengan langkah-langkah:**

The question is a question that uses Fibonacci numbers. Fibonacci is a sequence that starts from 0 and 1, then the next number is obtained by adding the two previous consecutive numbers.

1,1,2,3,5,8,13,21,34,55,**89**…

**Subject : **Math

**Class : **VIII ( Junior High School)

**Material : **Fibonacci Number

**Question code : **2

**Categorization code : **8,2

I hope this helps^^

## the difference between the tenth term and the seventh term

**Pertanyaan: **the difference between the tenth term and the seventh term of an arithmetic sequence is -60.the twelfth term divided by the sixth term is 2.find the first term and the common difference.

U10-U7= -60

a= first term , d= common difference

a+9d – (a+6d) = -60

a+9d -a -6d =-60

3d= -60

d= -20

U12/U6 = 2

U12=2U6

a+11d=2(a+5d)

a+11d=2a+10d

d=a=-20

## in arithmetic sequence, the sum of the first ten terms

**Pertanyaan: **in arithmetic sequence, the sum of the first ten terms is 125 and the third term is 5. Find the first term, the common difference and the sum of the first 15 terms

__Arithmetic Sequence__

__Arithmetic Sequence__

• * The nth term* (Un)

Un = a + (n – 1) b

• * The sum of the first n terms* (Sn)

Sn = n/2 × (a + Un)

Sn = n/2 × (2a + (n – 1) b)

a = the first term

b = the common difference

==================================

S₁₀ = 125

U₃ = 5

a = ?

b = ?

S₁₅ = ?

S₁₀ = 125

10/2 × (2a + (10 – 1) b) = 125

5 × (2a + 9b) = 125

2a + 9b = 25 … eq (1)

U₃ = 5

a + (3 – 1) b = 5

a + 2b = 5 … eq (2)

To find a and b, use the elimination/substitution

▪︎Find the first term

Eliminate variable b to find a

2a + 9b = 25 (×2)

a + 2b = 5 (×9)

4a + 18b = 50

9a + 18b = 45

___________ –

-5a = 5

a = -1

The first term is -1

▪︎Find the common difference

To find the common difference, substitute a = -1 to eq (2)

a + 2b = 5

-1 + 2b = 5

2b = 5 + 1

2b = 6

b = 3

The common difference is 3

▪︎Find the sum of the first 15 terms

S₁₅ = 15/2 × [2(-1) + (15 – 1)(3)]

S₁₅ = 15/2 × [-2 + (14)(3)]

S₁₅ = 15/2 × (-2 + 42)

S₁₅ = 15/2 × 40

S₁₅ = 15 × 20

S₁₅ = 300

The sum of the first 15 terms is 300.

Hope it helps.

## The first term of an arithmetic sequence is 14. The

**Pertanyaan: **The first term of an arithmetic sequence is 14. The fourth term is 32. Find the common

difference.

**Answer****:**

The n-th term of an arithmetic sequence is given by:

Un = a + (n – 1)b

Where a the first term, b the common difference. If U4 = 32 and a = 14 then

32 = 14 + (4 – 1)b

18 = 3b

b = 6

The common difference is 6

## Tolong Bantu jwb : 1.One term of an arithmetic sequence

**Pertanyaan: **Tolong Bantu jwb :

1.One term of an arithmetic sequence is T13 = 30. The common diffrence is d = 3/2

a. Find the first Term.

b. Write a rule for the nth term.

2. In an arithmetic series, T1 = 5 and T20 = 62.

a. Find the common diffrence.

2. Find the value of T15.

3. Find the sum of the first 40 terms. (S40)

3. Consider the arithmetic series 4+7+10+13+16+19+…

Find the sum of the first 30 terms. (S30)

#Tolong bantu jwb ya gk ada cara juga gpp. Thx Senin di kumpul

3. Arithmetic series

4 + 7 + 10 + 13 + 16 + 19 + …

a = 4 (first term), d = 3 (difference)

Sn = (n/2)(2a + (n – 1)d)

S10 = (10/2)(2(4) + (10 – 1)3)

= 175

## Find the first two terms of an arithmetic sequence if

**Pertanyaan: **Find the first two terms of an arithmetic sequence if the sixth term is 21 and the sum of the first seventeen terms is 0

**Jawaban:**

56 and 49

**Penjelasan dengan langkah-langkah:**

u6 = a + 5b = 21

s17 = 0

u9 = a + 8b = 0

-3b = 21

b = -7

a = 56

so the first two terms are 56 and 49

Tidak cuma jawaban dari soal mengenai **How To Find The Common Difference Of An Arithmetic Sequence**, kamu juga bisa mendapatkan kunci jawaban atas pertanyaan seperti Tolong Bantu jwb, in arithmetic sequence,, Find the sum, find the sum, and find the common.